∫−∞tx(τ)dτ↔FSbk=1jkω0ak for ≠0\int_{-\infty}^tx(\tau)d\tau \xleftrightarrow{FS} b_k = \frac{1}{jk\omega_0} a_k \text{ for } \ne 0∫−∞tx(τ)dτFSbk=jkω01ak for =0
