Seonglae Cho2017143020 조성래
7.2
(a). After application of the impulse invariance method,
(b). We can simply find the value by substituting given values to equations
By combining above 2 equations, Two variable and can be computed.
(c). are independent from because of impuse invariance.
8.1
(a). which means the sampled signal is periodic and period is 6
(b). Sampling rate and ’s Fourier series form denotes that the maximum frequency . Therefore the sampling rate is below the Nyquist rate.
(c).
By Fourier Series
8.4
(a). as well known function.
(b).
(c).
8.9
(a). when to obtain .
(b). Like problem (a), smallest which are bigger than band.
8.13
That means which are circularly shifted by 2
8.16
Original signal’s period is 6 and sampling resulting 4-point () inverse DFT. That means first two values are aliases with
8.28
(a).
(b). means -2 points circular shift
(c). This means sum from -2 shifted
(d). To ensure that no aliasing occurs, should be larger then the length of the linear convolution
(e). This linear convolution is same as circular convolution so result is periodic signal of with period 6
8.36
(a). for
(b). for to have the same DFT.
We can obtain answer by replicating with a period of 10 and extracting the 10 points.