Neumann series

Creator
Creator
Seonglae Cho
Created
Created
2025 May 20 17:53
Editor
Edited
Edited
2025 May 20 17:57
Refs
Refs

Condition

  • As a result, IAI−A has an inverse matrix

Results

Intuitively, same as
Geometric Series
k=0Ak  =  I+A+A2+  =  (IA)1\sum_{k=0}^{\infty} A^k \;=\; I + A + A^2 + \cdots \;=\; (I - A)^{-1}
 
 
 
 
 

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